Which answer is correct?

Use `new_list = old_list`. Assignment in Python copies the list.

— new_to_py

Use `new_list = old_list[:]`. Slice notation creates a shallow copy.

— slice_user

Use `new_list = old_list.copy()`. The `.copy()` method creates a shallow copy. For nested structures, use `copy.deepcopy(old_list)`.

— explicit_dev

Use `new_list = list(old_list)`. The list constructor creates a new list from any iterable.

— constructor_fan